Sql group by order by

I have a table of tags and want to get the highest count tags from the. In all versions of MySQL, simply alias the aggregate in the SELECT list, . One way to do this that correctly uses group by : select l. As of SQL standarts, in this case ORDER BY must influence only of GROUP BY , not data before grouping. I have a single table which I need to pull back the most recent records based on a userID and keying off of documentID (no duplicates). I am trying to run this sql query and it gives me a syntax error: SELECT.

TABLE : TABLE : To get ‘agent_code’ and ‘agent_name’ columns from the table . SELECT column_name(s) FROM table_name. GROUP BY column_name(s) ORDER BY column_name(s); . The ORDER BY keyword is used to sort the result-set in ascending or descending order. The SQL ORDER BY and GROUP BY tutorial explains how to organize data received from a database by using different SQL Keywords: GROUP BY, ORDER . SQL gives you options for retrieving, analyzing, and displaying the information you need with the GROUP BY, HAVING, and ORDER BY clauses.

Und wo ich das gerade in deinem Post sehe, wie kann ich hier SQL Code highlighten?